The Speed of a car travelling on a straight road is listed below at successive intervals of 1 s:
Time (s) | |
Time (s) |
Speed (m / s) |
0 |
0 |
1 |
2 |
2 |
4 |
3 |
6 |
4 |
8 |
Which of the following is/are correct?
The car travels:
Select the correct answer using the code given below
CONCEPT:
\({\rm{Average\;speed}} = \frac{{{\rm{Total\;distance\;travelled\;}}}}{{{\rm{Time\;taken}}}}{\rm{\;}}\)
CALCULATION:
Given - v = 8 m/s at t = 4 s
From the given table we can find uniform acceleration,
As we know that acceleration is defined as the rate of change of velocity i.e.,
\(a=\frac{{\Delta v}}{{\Delta t}} \)
\(\Rightarrow a=\frac{{\ 8}}{{\ 4}}=2\ {m/s^2} \)
Thus car travels with a uniform acceleration of 2 m / s2.Now displacement after 4 sec can be expressed as
\(s = ut + \frac{1}{2}a{t^2} = 0 + \frac{1}{2} \times 2 \times {4^2} = 16\;m\)
Thus displacement after 4 sec is 16 m.
For calculating average velocity
\(average\;velocity = \frac{{total\;displacement}}{{total\;time}} = \frac{{16 - 0}}{{4 - 0}} = 4\;m\;/\;s\)
Hence option 1, 2 and 3 are all correct